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Last modified
3/7/2025 2:45:30 PM
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eScc. TG u�r J7� �fr<" ��, _ Z �f. <br />t. CURVE TABLES. <br />' 1 2.3af o- epi a - J 2 - F <br />_ Publish6d,by KEUFFEL 6s ESSE' <br />ES.' <br />a3 r • �®1V USE CURVIE TA$a.: . <br />4 So � I �'- �'- <br />,r8 - �/—,��j[/l Table I. contains Tangents and'Externals to a 1° eurv. Tan. and <br />to any other radius may be found nearly enough, by dividding the Tan. <br />or Ext.; opposite the given Central Angle by the given degree of curve. <br />To find Deg. - of Curve;`having the Central Angle and Tangent: <br />Divide Tan. opposite the given Central Angle by the given Tangent. <br />To fihd_, Deg. of Curve, having the Central: Angle and External: <br />Divide Ext. opposite the given Central Angle by the given External. <br />To find Nat. Tan. and Nat: Ex. See. for. any angle by Table L: Tan. <br /><r or Ext. of twice the given angle divided by the radius of a 1° curve will <br />be the Nat. Tan. or Nat. Ex. See: <br />( ! EXAMPLE. . <br />uLI I Wanted a Curve with an Ext. of about 12 ft. Angle <br />_ <br />� of liitersection .or' I: P. =23° 20' to -Che R: at Station.-,` <br />f �J 542-72. <br />Ext. in Tab. I opposite 23° 20120.37 _ <br />120.87=.12=10.07. Say a 10° -Curve. \ <br />�" Il -3c F Tar. in Tab. I opp. 23° 20' =1183.1 <br />11$3.1: 10=118.31. - <br />`Correction for A. 23°, 20' fora 10° Cur. =0 <br />Qo+oa- 118:31+0.16=118:47.=corrected Tangent.1 <br />(If corrected E cl. is required find in same way) <br />L - r, Ang..23°20'=23.33° 10=2.3333=L. C: <br />p' Da r (39 'y qd� ��. � . c"' i 2° 13a'=def. for sta: 542" i'. P.—sta. 542+72 <br />- :. <br />tqs J N + 4° 49 ' _ <c a u } 50 Tan. — 1'.18,47 <br />°sly tt 2-r 7° r,.r x• fa.Kp F V 191'= " :: :a r. 543 S. C.=sta 541+'53.53 <br />9°"49,-r.= 50 2 .33.33 s <br />{ �, o -'• 11.040'.= « �: 543. L. C.= <br />k tir $6.86 E. C. =Sta: 543-{-86:86 <br />} t, i100_53:53=46.47X3'(def. for 1 ft. of 14° Cur.=139.41`;r <br />2 19a' =def. for st :. 542. <br />D'ef.'for 50 fE.-=2° 30' fora 10° Cur e. <br />Def. for 36.86 ft. =1° 5012' for a 10'° C e. <br />M v tea. r - . _ XIP .I.?.Ang.23'20' <br />r 1-73 <br />\\ \\ <br />�g�f� Ifl" Curve <br />YL T ,4GJ <br />1 -- <br />
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