|
Help
|
About
|
Sign Out
Home
Browse
Search
Pg 77
DaneCounty-Planning
>
Clerical
>
Sam
>
Fricky
>
FBs
>
408
>
Pg 77
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
3/10/2025 11:50:16 AM
Creation date
3/10/2025 11:50:14 AM
Metadata
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
Page 1 of 1
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
Show annotations
View images
View plain text
I'1. <br />::CURVE- <br />& ESSER-CO <br />� <br />Published by KEUFFEL ' <br />HOW 'TO USE CURVE TABLES <br />Table I: contains Tangents:and Externals to a 1° curve. Tan. and <br />Ext. to any other radius Ypay be found nearly enough, by dividing theTan. <br />} ! <br />�r Ext. oppo? ite the given Central. Angle by the given degree.of curve. <br />I To find Deg. of Curve, having the Central -Angle and Tangent: <br />i ivide Tan. opposite the given Central Angle by the given Tangent. <br />-To find Deg_. of Curve, having the Centras. Angle and'External: <br />p , <br />(Divide Ext. opposite the given Central Angle.by the given External. <br />find. Nat. Tan: and Nat. Ex. See. for any angle by Table I.: Tan. <br />.,To <br />ar Ext. of twice the given angle -divided by the radius of a 1° curve,will <br />be the Nat. Tan. or Nat.'Ex. See. <br />EXAMPLE <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />dor P.=23° 20' the R. at' Station <br />of Intersection .1:. -to. <br />• <br />542-�72. ' '. <br />�ii <br />Ext. in Tab. I opposite 23°.20' 2120.87 <br />120.87--12=10.07. Say a 10° Curve. <br />Tan in Tab I opp 23' 20'=1183.1 <br />;1-183.1-i-tf)=118.31: <br />....° <br />' - Correction for A 23o '20 -[ora 10 : Cur. =0.16 t <br />r <br />118.31-}-0 16 —118 47 = corrected Tangent. <br />(If corrected Fxt is required find in same way) <br />Ang.23° 20'=23.33°-10=2.3333=L. C. <br />2°'19%'- def. for sta. 542 <br />_I'. P.=sta. 542+72 <br />+50 <br />Tan.'=1 ..:18.47 '- <br />--'• 7 = ° 192' .0 °. 543 <br />S. C.=sta. 541-X53.53 <br />11* 40,.= u . « �.. 543 } . <br />L. C. __ 2 .33.33 <br />4 <br />I'1. <br />::CURVE- <br />& ESSER-CO <br />� <br />Published by KEUFFEL ' <br />HOW 'TO USE CURVE TABLES <br />Table I: contains Tangents:and Externals to a 1° curve. Tan. and <br />Ext. to any other radius Ypay be found nearly enough, by dividing theTan. <br />} ! <br />�r Ext. oppo? ite the given Central. Angle by the given degree.of curve. <br />I To find Deg. of Curve, having the Central -Angle and Tangent: <br />i ivide Tan. opposite the given Central Angle by the given Tangent. <br />-To find Deg_. of Curve, having the Centras. Angle and'External: <br />p , <br />(Divide Ext. opposite the given Central Angle.by the given External. <br />find. Nat. Tan: and Nat. Ex. See. for any angle by Table I.: Tan. <br />.,To <br />ar Ext. of twice the given angle -divided by the radius of a 1° curve,will <br />be the Nat. Tan. or Nat.'Ex. See. <br />EXAMPLE <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />dor P.=23° 20' the R. at' Station <br />of Intersection .1:. -to. <br />• <br />542-�72. ' '. <br />�ii <br />Ext. in Tab. I opposite 23°.20' 2120.87 <br />120.87--12=10.07. Say a 10° Curve. <br />Tan in Tab I opp 23' 20'=1183.1 <br />;1-183.1-i-tf)=118.31: <br />....° <br />' - Correction for A 23o '20 -[ora 10 : Cur. =0.16 t <br />r <br />118.31-}-0 16 —118 47 = corrected Tangent. <br />(If corrected Fxt is required find in same way) <br />Ang.23° 20'=23.33°-10=2.3333=L. C. <br />2°'19%'- def. for sta. 542 <br />_I'. P.=sta. 542+72 <br />+50 <br />Tan.'=1 ..:18.47 '- <br />--'• 7 = ° 192' .0 °. 543 <br />S. C.=sta. 541-X53.53 <br />11* 40,.= u . « �.. 543 } . <br />L. C. __ 2 .33.33 <br />86.86 E. C. — Sta. 543+86.86 <br />100-53.53 =46.47 X3'(def. for l ft. of 10° Cur.)`=139.41' <br />2° 19''=def. for sta. 542. 9 <br />Def; for 50 ft. =2° 30' for a 10° Curve. i <br />+ Def. for 36.86 ft. -1° 501' for a 10° Curve. <br />oto - xr <br />cc <br />1c <br />o i <br />4 <br />• } AS• <br />
The URL can be used to link to this page
Your browser does not support the video tag.