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CURVE TABLES. j Published by KEUFFEL 8s ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a F curve. Tan. and 1�Ext. toanyotherradius may,befoundnearly enough, bydividing theTan. or Ext. opposite the given Central Angle by the given degree of curve. ,j To find Deg. of Curve, having the Central Angle and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. To find Deg. -of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. and Nat. Ex: Sec. for any "angle by Table I.: Tan. or Ext. of twice the given angle divided by the radius of a 1' curve will be the Nat. Tan. or Nat. Ex. Sec. EXAMPLE. 1�7anted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P. =23' 20'. to the R. at Station 542+72. Ext. in Tab. I opposite 23' 20' =120.87 1 --120.87=12=10.07. Say a 10' Curve. Tan. in Tab. I opp. 23' 20' =1183.1 1183.1=10=118.31. Correction for A. 23'.20' for a 10` Cur. =0.16 118.31-{-0.16=118.47=corrected Tangent. (If corrected Ext. is required find in same way) Ang.23'20'=23.33'=10=2.3333=L. C. 2° 193'=def. for sta. 542 I. P: =sta. 542-}-72 4' 491' = " -x-50 Tan. = 1 .18.47 7' 19"' = rt it it 543 c . L « 1i l{ B. C. =sty. u41 53.53 90 49 "= -{-50 11' 40'= a it is 543+ L. C.= 2 .33.33 86.86 E. C.=Sta. 543-{-86.86 100-53.53=46.47X3'(def. for 1 ft. of 1.0' Cur.) =139.41'= 2' 192'= def. for sta. 542. 1 . Def, for 50 ft. =2' 30' for a 10' Curve. Def. for 36.86 ft.= 1' 50" for a 10' Curve. Ida? F 31- 1 st 1r1 hl!- L 2jf�fs�� � r — — - A CURVE TABLES. j Published by KEUFFEL 8s ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a F curve. Tan. and 1�Ext. toanyotherradius may,befoundnearly enough, bydividing theTan. or Ext. opposite the given Central Angle by the given degree of curve. ,j To find Deg. of Curve, having the Central Angle and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. To find Deg. -of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. and Nat. Ex: Sec. for any "angle by Table I.: Tan. or Ext. of twice the given angle divided by the radius of a 1' curve will be the Nat. Tan. or Nat. Ex. Sec. EXAMPLE. 1�7anted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P. =23' 20'. to the R. at Station 542+72. Ext. in Tab. I opposite 23' 20' =120.87 1 --120.87=12=10.07. Say a 10' Curve. Tan. in Tab. I opp. 23' 20' =1183.1 1183.1=10=118.31. Correction for A. 23'.20' for a 10` Cur. =0.16 118.31-{-0.16=118.47=corrected Tangent. (If corrected Ext. is required find in same way) Ang.23'20'=23.33'=10=2.3333=L. C. 2° 193'=def. for sta. 542 I. P: =sta. 542-}-72 4' 491' = " -x-50 Tan. = 1 .18.47 7' 19"' = rt it it 543 c . L « 1i l{ B. C. =sty. u41 53.53 90 49 "= -{-50 11' 40'= a it is 543+ L. C.= 2 .33.33 86.86 E. C.=Sta. 543-{-86.86 100-53.53=46.47X3'(def. for 1 ft. of 1.0' Cur.) =139.41'= 2' 192'= def. for sta. 542. 1 . Def, for 50 ft. =2' 30' for a 10' Curve. Def. for 36.86 ft.= 1' 50" for a 10' Curve.