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• �'1�,' _ l_.6 -cwt, �, . <br />.GJi' . <br />0 <br />/ ` V. <br />,t.6 v L <br />T <br />TRIGONOMETRIC FORMULtE <br />B B <br />c a c a ° a <br />C A b G�yA: b C <br />`Right Triangle Oblique Triangles <br />Solution of Right Triangles <br />For Angle A. sin = ,cos= b ,tan= a , cot = a , see = "Cosec cose= o <br />c c b a b a <br />Given Required i z <br />tan -4=1= b cotB, c= 1 a2 -I z a 1 T <br />z <br />a, c A, B, b1 sin A = = cos B, b = %) (c+a (c—a) = c 1— az <br />p c o <br />A, a B, A c B=90°—A, b= a cotA, c= <br />sin A. <br />A, b B, a, c B=90°—A, a= Ytan A, c= b <br />f cos A. <br />A, c B, a, b 'B=90°—A, a -.csinA,:b= ccos A,_ <br />h Solution of Oblique Triangles <br />Given Required _ a sin B a sin C' <br />CA, B, a b, c, G' b sin A ' C = 180°—(A -)- B), c = sin _4 <br />. b sin A it sin C <br />A, a, b. B, c, C sin B= a ,C = 1fi0°—(A -r B), c = sin A <br />a, b, C A, B, c -4+B=180°-G', tan- (A—B)=(°'—b) ¢n r �A+73), <br />l _ a sin C + <br />c sin A <br />a, b, c A, B, C- s= 2 ,sinzA=ll. b c <br />(,' a)(s—e) <br />sin.8= ac C=180* -4.+B) <br />a, b, c Area s=a f 2+c, area = 1%8(8-2) (s—b) (s—c <br />A, b;_ e. Area b c sin A. <br />area = •- 2 <br />A, B, C, a. Area area = a sin B sir. C <br />2 sin A <br />REDUCTION TO HORIZONTAL <br />Horizontal distance=Slope distance multiplied by the <br />cosine of the vertical angle. Thus: slope distance =319.4 ft <br />'Ne Vert. angle=5° 10'. From Table, Page 1%. cos 5- iiy= <br />c a� n 9959. Horizontal distance=319.4X.9959=318.09 ft. <br />510 P�g1e Horizontal distance also=Slope distance minus slope <br />distance times (1—cosine of vertical angle). With the <br />ve same figures as in the preceding example, the follow - <br />Horizontal distance ing result is obtained. Cosine 50 lo'=.9959.1—.9959=.0041. <br />319.4X.0041=1.31. 319.4-1.31=318.09 ft. <br />When the rise is known, the horizontal distance is approximately:—the slope dist- <br />ance less the square of the rise divided by twice the slope distance. Thus: rise=14 ft., <br />slope distance=302.6 It. Horizontal distance=309.6— 14 X 14 =302.6-0.32=302.28 fL <br />2 X 302.6 <br />WADE IN U.S.A. <br />