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CURVE .T ELESe Published' by KEUFFEL ESSER CO. HOS!' TO USE CJRYE TABLE.S.: Table I. contains Tangents and Externals to a 10 curve: Tan- and Ext.. to any other radius maybefoundnearly enough, by dividing theTan. -or Ext. opposite the given Central Angle by -'the given degree of curve. To find Deg, of Curve, having the Central -Angle-and Tangent: Divide Tan. opposite the given'Central Angle by the given Tangent. To ,find Deg. of Curve, having the Central Angle and Externa.f: Divide Ext. opposite the given Central tingle by the given External. To find Nat. Tan, and Nat. Ex: Sec. for any angle by Table I,: Tan. or Ext. of twice the given ap_gle divided by the radius of a 1' curve will be the Nat. Tan. or Nat. B, k. See. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle . of Intersection . or 1. R=23' 20' to the R. at Station 542-x.72. Ext. in Tab. I oppositc 230-20' =120_$7 120:87.12=10.07. Say a 10° Curve. Tan. in Tab: I opp. 23' 20' =1.183.1 Correction foCA. 23' 20' for a 1.0° Cur, =0.16 11831+0.16 =118.47 = corrected Tangent. (If corrected Ext.is required find in same -AY) Ang. 23'.20'=23.33'-10=2.3333,=L. C. 2' 1912'= def. forsta. 542 I- P.=sta. 542-72 .4° 49,!'= " " -x-50 Tan. = :1 .18.47 7' 1912'= " 543 B. C. = sta. 541+53.53 9� 49;' — « cr t - +50. L. C. = 2.. 33.33 11° 40'= �: « 54,3+ 86.86 E. !C.=Std. 543 I X5.86 ' 100-53.53=46.47X3'(def.. for 1 ft. of 10° Cur.) =139.41'= 2` 10"=cleF. £ Or' sta. 542: - Def. fur 50 ft. =2' 30' for a 10° Curve. ,+ Def. far 36.SG ft. =1' 50' for a 10 Curve. A t CURVE .T ELESe Published' by KEUFFEL ESSER CO. HOS!' TO USE CJRYE TABLE.S.: Table I. contains Tangents and Externals to a 10 curve: Tan- and Ext.. to any other radius maybefoundnearly enough, by dividing theTan. -or Ext. opposite the given Central Angle by -'the given degree of curve. To find Deg, of Curve, having the Central -Angle-and Tangent: Divide Tan. opposite the given'Central Angle by the given Tangent. To ,find Deg. of Curve, having the Central Angle and Externa.f: Divide Ext. opposite the given Central tingle by the given External. To find Nat. Tan, and Nat. Ex: Sec. for any angle by Table I,: Tan. or Ext. of twice the given ap_gle divided by the radius of a 1' curve will be the Nat. Tan. or Nat. B, k. See. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle . of Intersection . or 1. R=23' 20' to the R. at Station 542-x.72. Ext. in Tab. I oppositc 230-20' =120_$7 120:87.12=10.07. Say a 10° Curve. Tan. in Tab: I opp. 23' 20' =1.183.1 Correction foCA. 23' 20' for a 1.0° Cur, =0.16 11831+0.16 =118.47 = corrected Tangent. (If corrected Ext.is required find in same -AY) Ang. 23'.20'=23.33'-10=2.3333,=L. C. 2' 1912'= def. forsta. 542 I- P.=sta. 542-72 .4° 49,!'= " " -x-50 Tan. = :1 .18.47 7' 1912'= " 543 B. C. = sta. 541+53.53 9� 49;' — « cr t - +50. L. C. = 2.. 33.33 11° 40'= �: « 54,3+ 86.86 E. !C.=Std. 543 I X5.86 ' 100-53.53=46.47X3'(def.. for 1 ft. of 10° Cur.) =139.41'= 2` 10"=cleF. £ Or' sta. 542: - Def. fur 50 ft. =2' 30' for a 10° Curve. ,+ Def. far 36.SG ft. =1' 50' for a 10 Curve. A