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3L -7 76 S� g /0 CURVE TABLES. - g Published by KEUFFEL a- ESSER . CO. Z HOW=�TO.USE CURVE TABLESa-.10 curve. Tan. alld . S to Table I. contains Tangents andExaeilnenou h,bydi idingtheTan�'J�✓� ` Ext. to any other radius may be found ne y g. or Ext. opposite the given.Central Angle by the given degree of curve. To find Deg. of Curve; having the Central Angle and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. 'To find Deg. of Curve, having the Central Angl ea d External: Ext. oposite the givenxternal pCentral Angle by the given To find Nat. Tsn. and Nat. Ex. Sec. for any angle by Table I.: Tan. or Ext. of twice the given angle divided by the radius of a 1° curve will be the Nat. Tan: or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P.=23° 20' to the R.-at_S.tation� 542-L72. E10�S7T31 b. I 023* 20' 120.87 10.07. Say a 10° Curve. g/ Tan. in Tab. I opp. 23° 20' =1183.1 S .y 44 1183.1-10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 118:31-}-0.16 =118.47 =corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23° 20'=23.33°=10=2.3333=L. C. 2° 19 '= def. for sta. 542 T. P—sta 5. 1 I.18 ' Z? ? I, _ « as « +50 Tan. = 1 .18.47 � 4-4 9 i1 -7-z- 7 0 7° 191'= t: 543 B. C.=sta_ 541+53.53 T—S-6 - 9° 491' _ . " " +50 I C. _ . 2.33.33 lio 40, 543 86.86 E. C. =Sta. 543+SG.86 5 100-53.53=46.47 X3'(def. for 1 ft. of 10° Cur.) =139.41'= Yy 2° 19 ' adef. for sta. 542. Def. for 50 ft. =2° 30' for a 10° Curve. Z-1 7 Def. for 36.56 ft. 1* 501' for a 10° Curve. i S4 - �2 I.P.An9.23.20' N /,e ,� 4A P f0• Curve y� P 4d/ v xi dye f• S � � � ;. j it � � i � • XIr 6 27 ,65 75' /�� L 7L L/` � � - 3L -7 76 S� g /0 CURVE TABLES. - g Published by KEUFFEL a- ESSER . CO. Z HOW=�TO.USE CURVE TABLESa-.10 curve. Tan. alld . S to Table I. contains Tangents andExaeilnenou h,bydi idingtheTan�'J�✓� ` Ext. to any other radius may be found ne y g. or Ext. opposite the given.Central Angle by the given degree of curve. To find Deg. of Curve; having the Central Angle and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. 'To find Deg. of Curve, having the Central Angl ea d External: Ext. oposite the givenxternal pCentral Angle by the given To find Nat. Tsn. and Nat. Ex. Sec. for any angle by Table I.: Tan. or Ext. of twice the given angle divided by the radius of a 1° curve will be the Nat. Tan: or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P.=23° 20' to the R.-at_S.tation� 542-L72. E10�S7T31 b. I 023* 20' 120.87 10.07. Say a 10° Curve. g/ Tan. in Tab. I opp. 23° 20' =1183.1 S .y 44 1183.1-10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 118:31-}-0.16 =118.47 =corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23° 20'=23.33°=10=2.3333=L. C. 2° 19 '= def. for sta. 542 T. P—sta 5. 1 I.18 ' Z? ? I, _ « as « +50 Tan. = 1 .18.47 � 4-4 9 i1 -7-z- 7 0 7° 191'= t: 543 B. C.=sta_ 541+53.53 T—S-6 - 9° 491' _ . " " +50 I C. _ . 2.33.33 lio 40, 543 86.86 E. C. =Sta. 543+SG.86 5 100-53.53=46.47 X3'(def. for 1 ft. of 10° Cur.) =139.41'= Yy 2° 19 ' adef. for sta. 542. Def. for 50 ft. =2° 30' for a 10° Curve. Z-1 7 Def. for 36.56 ft. 1* 501' for a 10° Curve. i S4 - �2 I.P.An9.23.20' N /,e ,� 4A P f0• Curve y� P 4d/ v xi