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CURVE TABLES. Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a 1° curve. Tan. and East. to any otherradiusmay befoandnearly enough, by dividing theTan. or Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central Angle and Tangent: Divide Tan. opposite the given Central "Angle by the given Tangent. To find Deg, of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. ar_d Nat. Ex. Sec. for any angle by Table L: Tan. or -Ext. of twice the given angle divided by the radius of a 1' curve will be the Nat. Tan, or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angl¢ of .Intersection or 1. P.=23* 20' to the R. at Station .542+72. Ext. in Tab. I opposite 23° 20' =120.87 120.87=12=10.07. Say a 10' Curve. Tan. in `fab. I opp. 23° 20'=1183:1 11$3.1 10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 118.31+0.16=118.47 —corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23' 20'=23.33 =10=2.3333=L. C. 2° 192'=def. for ata. 542 1. P. =sta. 542+72 4* 49'2'= n d c +50 Tan.= 1 .18.47 7.1911= " " a 543 9' 49,= « 50 B.C. =sta: 541+53.53 11040' = u a 543 } L. C. = 2. 33.33 86.86 E. C. =Stn. 543+86.86 100-53.53=46.47X3'(def. for 1 ft: of 1.0° Cur.) =139.41'= 2' 192' =def. for sta. 1942. Def. for 50 ft. =2° 30' for a 10° Curve'. Def. for 36.86 ft. =1° 502' for a 10° Curve. �J l� J ffs ,357-30 ld 5 - �4 32 - z � ✓ � —o a ,sem 6f X90-10 1-3o 5'V 6z ry NJ fi. CURVE TABLES. Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a 1° curve. Tan. and East. to any otherradiusmay befoandnearly enough, by dividing theTan. or Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central Angle and Tangent: Divide Tan. opposite the given Central "Angle by the given Tangent. To find Deg, of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. ar_d Nat. Ex. Sec. for any angle by Table L: Tan. or -Ext. of twice the given angle divided by the radius of a 1' curve will be the Nat. Tan, or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angl¢ of .Intersection or 1. P.=23* 20' to the R. at Station .542+72. Ext. in Tab. I opposite 23° 20' =120.87 120.87=12=10.07. Say a 10' Curve. Tan. in `fab. I opp. 23° 20'=1183:1 11$3.1 10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 118.31+0.16=118.47 —corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23' 20'=23.33 =10=2.3333=L. C. 2° 192'=def. for ata. 542 1. P. =sta. 542+72 4* 49'2'= n d c +50 Tan.= 1 .18.47 7.1911= " " a 543 9' 49,= « 50 B.C. =sta: 541+53.53 11040' = u a 543 } L. C. = 2. 33.33 86.86 E. C. =Stn. 543+86.86 100-53.53=46.47X3'(def. for 1 ft: of 1.0° Cur.) =139.41'= 2' 192' =def. for sta. 1942. Def. for 50 ft. =2° 30' for a 10° Curve'. Def. for 36.86 ft. =1° 502' for a 10° Curve.