Laserfiche WebLink
IS -7 <br />f <br />N <br />s� <br />i <br />1 <br />v <br />ti <br />I <br />I <br />I <br />CURVE_ •TABLES. - <br />published by KEUFFEL 81, ESSER CO: <br />now 'r®. USE _CURVE TABLES. <br />Table I. contains Tangents and Externals to s 1°el . d vidan. and <br />arveling theTan. <br />t. to any other radius maybe found nearly the g� en degree of curve. <br />Ext. site the glven'Central Angle by <br />To find Deg. of Curve, having the Central Angliven Tangnt Tangent: <br />vide Tan. opposite the given Central Angle by the g <br />To find Deg., of Curve, having the Central Angle and External: <br />vide Ext. opposite the given Central Angle by the given External. <br />See. f or any an gle' <br />To find Nat. Tan- and Ngle divided by the ad_ us of a lbcurve will <br />of twice the given <br />the Nat. Tar_. or Nat. Ex EXAMPLE. <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection or .1 • P. =23°. 20'. to the R. at Station <br />542+72• <br />Ext. in Tab. I opposite 23' 20 =120''3-� <br />120.57=12=10.07. Say a 10° Curve. <br />Tan. in Tab. I opp. 23° 20'= 119.3-1 <br />-1183.1=10=118:31., <br />Correction for A. 23° 20' for a 10' Cua•. =0.16 <br />115.31 0.16 =115.47 = corrected Tang <br />(If corrected l,xt. is reuired find in 333 ame L. CaY) <br />_ Aug. 23° 20' <br />=23-33'—'1 542+72 <br />20 19-2'=def . for sta. 542 I. P.•=sta. 1_ 18.47 <br />4° 491' = a « u } 50 Tan. _ <br />7° 191'= " ° 11 543 B. C•=sta. • 541+53.53 <br />9° 491' = u a u 15p 2 .33.33 <br />543+ L. C. _ <br />11° 40' _ " " 543+86-36 <br />• 86-.86- E. C. =Sta. <br />100-53.53=46.47X3'(def�for 1 ft, of 10° Cur.) =139.41'= <br />2° loll=def. for sta. 542. - <br />Def. for 50 ft. =20 30' for a 10° Curve. <br />Def. for 36.86 ft.=1° 501' for a 1W Curve. <br />' 3y <br />�X <br />1 <br />'A0_ <br />10° Curve,\ <br />N <br />s� <br />