Laserfiche WebLink
CURVE ' TABLES. <br />Published by• KEUFFEL & ESSER CO. <br />HOW TO USE CURVE TABLES. <br />Table I. contains Tangents and Externals to a V curve. Tan. and <br />Ext. to any other radius may be f ound nearly enough, bydividing theTan. <br />or Ext. opposite the given Central Angle by the given degree of curve. <br />To find. Deg. of Curve, having the Central Angle and Tangent: <br />— Divide Tan. opposite the given Central Angle by the given Tangent. <br />To find Deg. of Curve, having the Central Angle and External: <br />— Divide Ext. opposite the given Central Angle by the given External. <br />To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tan. <br />— or Ext. of twice the given angle divided by the radius of a 1° curve will <br />— I be the Nat. Tan. or Nat. Ex. Sec. <br />EXAMPLE. <br />— I Wanted a Curve with an Ext. of about 12 it. Angle <br />of Intersection or I. P.=23'-20' to'the R. at Station <br />542+72. <br />Ext. in Tab. I opposite 23° 20' =120.87 <br />_ 120.87-12=10.07. Sava 10° Curve. <br />Tan. in Tab. I opp. 23° 20'= 1183.1 <br />1183.1=10 =118.31: <br />Correction for A. 230 20' for a 10° Cur. =0.16 <br />118.31- 0.16=118.47=corrected Tangent. <br />(If corrected Ext: is required find in same way) <br />Ang. 23°20'=23.33° - 10=2.3333=L. C. - <br />2° 19l'=dcf.for sta. 542, I. P.=sta. 542+72 <br />4049121- ?c+50 Tan. = 't .18.47 <br />7' 19', : 543 <br />— I 90 49" <: +50 B. C. =sta. 541+53.53 <br />11°40'= :" 54.3+ L. C.=, 2 .33.33 <br />86.86 E. C.=Sta. 543+86.86 <br />100-53.53=46.47 X3'(def. for 1 ft. of 10° Cur.)'=139.41'= <br />2° 191'=def. for sta. 542: . <br />Def. for 50 ft. =2° 30' for a 10' Curve. ' <br />Det. for 36.86 ft. =1° 50',-' for a 10° Curve. <br />