Laserfiche WebLink
'All a /.,, oe_ iT 5 A4AI . I . 151/ <br />TRIGONOMETRIC FORMULAE <br />B B B <br />a ca a <br />N <br />C At b C A b C <br />Right Triangl; Oblique Triangles <br />Solution of Right Triangles <br />-For Angle A. sin = Dcos = @ tan = cot = a , sec cosec = a <br />Given Required <br />a b A, B,c tan A cot B, oc N/ -a-2—+72 + <br />b + 7a, <br />7-2 <br />a, e. A, B, b sinA=2�=cos B,b=\1(a+a)(r_—a)=c 1— a — <br />. a 02 <br />A, a B, -b,. o B=90°—A, b= a cotA, o= a <br />sin A. <br />A, b B, a, c B = 90'=A, a. = b tan A, c = b <br />cos.A. <br />A, c. B, a, b B = 90*—A, a = c sin A,b,_cos <br />Solution of Oblique Triangles <br />Given Required b = asin B, asin C <br />A, B, a b, o, C C = 180*—(A + B) , c <br />sin A sin A <br />b sin AC = 180'—'(A + B), c = a -sin C <br />sin , <br />A, a, b B, c, C a sin A <br />(A <br />b, C A, B, o A+B=180*— C, tan I —B)= <br />(a—b) tan 1, (A+B) <br />a sin 0 a+ b - <br />sin A <br />a, b, a A, B, C=a+b+ "in',A=-V 1 b <br />2 <br />sin ,'B= -\l a c 0=1$0'--(A+B) <br />b <br />a, b, o Area 8=a+2+area = Nls(8 aTT8 s <br />A, b, e Area area = b c sin A <br />2 <br />a' sin B sin C <br />A, B, 0, a Area area = 2 sin A <br />REDUCTION TO.HORIZONTAL <br />Horizontal distance =Slope distance multiplied by the <br />'Ce cosine of the vertical 29110nh us: slope distance =319.4 ft. <br />Vert. angle =50 101. From Table, Page IX. cos 50 10/= <br />e 9959. Horizontal distance=319.4X.9959=318.09 ft. <br />61�:10 <br />Horizontal distance also�Slope distance minus slope <br />I ve� Ie- <br />P",%*e 'distance times (1—cosine of vertical angle). With the <br />e. same figures as in the Preceding example, the follow- <br />ing result is obtained. Cosine 50 101=.9959.1—:9959=.0041. � <br />Horizontal distance 319.4X.0041=1.31.319.4-1.31=318.09 ft. <br />When the rise is known, the horizontal distance is approximately:—the slope dist- <br />ance less the square of the rise divided by twice the slope distance. Thus: rise =14 ft., <br />slope distance=302.6 ft. Horizontal distance=302.6— 14 X 14 =302.6-0.32=302.28 ft. <br />2 X 302.6 <br />WE W U. 46& <br />