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Ulm <br />Ulm <br />CURVE TABLES'. <br />Published by KEUFFEL 8ti ESSER CO. <br />:HOW TO.USECURVE TABLES. <br />Tabie'l.- contains Tangents and Externals to I* curve. Tan.and <br />Ext. ' to any other radius may befound nearly enough, by dividing theT - an. <br />or. Ext. opposite- the given Central Angle by the given degree of! curve. <br />To find Deg. of Curve, having the Central Angle and Tangent: <br />Divide Tan. opposite the given Central Angle by the given: Tangent. <br />I <br />To find Deg. of Curve, having the Central -Angle and External: <br />Divide Ext. opposite the given Central Angle by th6lgivbn External. <br />... To find Nat. Tan. and Nat. Ex. Sec. for any.angle by Table I.: Tan. <br />or Ekt. of twice the given . angle divided by the radius of, a1O curve will <br />bethe Nat. Tan. or - Nat. Ex. .Sec: <br />EXAMPLE. <br />Wanted a Curve with an Ext. of about 12'ft. Angle, <br />of Intersection or L. P.=23° 201 to the R. -at -Station <br />542+72. <br />Ext. in Tab -4 opposite 23* 20, = 120.87 <br />120.87 12 10.07. Say a 10° Curve. <br />Tan. in Tab. I opp. 23* 20'= 1183.1 <br />.1183.1+10=118.31. - <br />Correction for A. 23* 20' -for a 10° Cur. =0.16 <br />.118.31+0.16 =118.47 =c'orrected Tangent. <br />(if corrected Ex't. is required find in same way) <br />Ang.-23*,20'=23.33*­ 10=2.3333=L. C. <br />2* 191'= def. -for sta., 1. P. sta. 542+72 <br />40 49" 44 a +50 Tari. 1'. 18.47 <br />543. <br />90 491'= B. C. = sta. 541+53.53 <br />, +50 <br />11' 40'-543+ L. C.= 2 .33.33 <br />-86.86 E. C. '.- Sta. 543+86.86 <br />100-53.63=46.47X3'(def. for I ft. of 10° Cur.)'=139.41'= <br />2 .1,9.def. for std. 542. <br />Def. for SOft.=2930'fora lOq;Curve: <br />Def. for 36.86 ft. =1° 50V for a 10° Curve. <br />tx <br />000, <br />