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CURVE. TABLES. Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a V curve. Tan. and Ext. to any other radius maybe found nearly enough, by dividing the Tan. or Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central.Angle'and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. To find Deg. of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tarn. or Ext. of twice the given angle'divided by the radius of a 1° curve will be the Nat. Tan. or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P.=23*. 20' to the R. at Station 542+72. Ext. in Tab: 1 opposite 231 20' =120.87 120.87—.,12=10.07. Say a 10° Curve. Tan. in Tab. I opp. 23°20'=1183.1 1183.1=10=118.31. ' Correction for A. 23° 20' for a 10° Cur. =0.16 118.31+0-167 118.47 =corrected Tangent. (If corrected Ext. is.required find in same way) Ang.23°20'=23.33°=10=2.3333=L. C. 2° 19;'=def. for sta. 542 I. P. =sta. 542+72 4° 49;'' " +50 Tan. = 1 .18.47 - 7° 1912'= « a a 543 90 491;— " f° '� +50 B' C. = sta. 541+53.53 11°40'= " " f° 543+ L. C.= 2 .33.33 86.86 E. C. = Sta. 543+86.86 100-53.53=46.47X3'(def. for 1 ft. of 10° Cur.) =139.41'= 2°.19'=def. for sta. 542. ef D. for 50 30' for a 10° Curve. Def: for 36.86 ft. =1° 504' for a 10° Curve. E - e �{•.S- 02 • .o / � i �� 9 ri0o moo .s7 8 ¢ 099, C--8 . 3 2-6 .7-f- AR2 8.34 . a 4 927.&1-, 887,J7 C - /.,I -7X 3,8 99 , .Z 889,6 C- 8.s 7 ' a z zs ¢. Z - 7-4a- -4 3 -7- 7-1-4V %1, iZ 99 C-7.36 8f 7,.4C- �Ao ,0897, o.I/ C-- 7,,e 3 V31 3 • z.S-1 9 98 9,999-2s- C-8 . CURVE. TABLES. Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES. Table I. contains Tangents and Externals to a V curve. Tan. and Ext. to any other radius maybe found nearly enough, by dividing the Tan. or Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central.Angle'and Tangent: Divide Tan. opposite the given Central Angle by the given Tangent. To find Deg. of Curve, having the Central Angle and External: Divide Ext. opposite the given Central Angle by the given External. To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tarn. or Ext. of twice the given angle'divided by the radius of a 1° curve will be the Nat. Tan. or Nat. Ex. Sec. EXAMPLE. Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or I. P.=23*. 20' to the R. at Station 542+72. Ext. in Tab: 1 opposite 231 20' =120.87 120.87—.,12=10.07. Say a 10° Curve. Tan. in Tab. I opp. 23°20'=1183.1 1183.1=10=118.31. ' Correction for A. 23° 20' for a 10° Cur. =0.16 118.31+0-167 118.47 =corrected Tangent. (If corrected Ext. is.required find in same way) Ang.23°20'=23.33°=10=2.3333=L. C. 2° 19;'=def. for sta. 542 I. P. =sta. 542+72 4° 49;'' " +50 Tan. = 1 .18.47 - 7° 1912'= « a a 543 90 491;— " f° '� +50 B' C. = sta. 541+53.53 11°40'= " " f° 543+ L. C.= 2 .33.33 86.86 E. C. = Sta. 543+86.86 100-53.53=46.47X3'(def. for 1 ft. of 10° Cur.) =139.41'= 2°.19'=def. for sta. 542. ef D. for 50 30' for a 10° Curve. Def: for 36.86 ft. =1° 504' for a 10° Curve.