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CURE TABLES. <br />Published by KEUFFEL & ESSER CO. <br />HOW . TO USE CURVE TABLES. <br />Table I. contains Tangents and Externals to a V curve. Tan. and <br />Ext. to any other radius may be f ound nearly enough, by dividing the Tan. <br />or Ext, opposite the given Central Angle by the given degree of curve. <br />To find Deg. of Curve, having the Central Angle and Tangent: <br />Divide Tan. opposite the given Central Angle by the given Tangent. <br />To find Deg. of Curve, having the Central Angle and External: <br />Divide Ext. opposite the given Central Angle by the given External. <br />To find Nat. Tan, and Nat. Ex. Sec. for any angle by.Table I.: Tan. <br />or Ext. of twice the given angle divided by the radius of a 1° curve will <br />be the Nat. Tan. or Nat. Ex. Sec. <br />EXAMPLE. <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection or 1. P.=23* 20' to the . R. at Station <br />542+72. <br />Ext. in Tab. I opposite 23°.20' =120.87 <br />120.87=12=10.07. Say a 10° Curve. <br />Tan. in Tab. I opp. 23° 20'=1183.1 <br />1183.1=10 =118.31. <br />Correction for, A. 23° 20' for a 10° Cur. =0.16 <br />118.31+0.161= 118.47 =corrected Tangent. <br />(If corrected Ext. is required find in same way) <br />Ang. 23° 20'=23.33°=10=2.3333=L. C. <br />2° 1921'= def. for sta. 542 1. P.=sta. 542+72 <br />V 49 z' _ "1 +50 Tan. = 1 .18.47 <br />T 19,' _ <br />9° 491' = " " t� `/ f0 +50 543 <br />B. C. = sta. 541 153.53 <br />110 40' " « 548+ L. C.= 2'..33.33 <br />' 86.86 E. C.=Sta. 543+86.86 <br />100-53.53=46.47X3:(def. for 1 ft. of 10° Cur.) =139.41'= <br />20 192'=def. for sta. 542. <br />Def. for 50 ft. =2° 30' for a 10° Curve. <br />Def. for 36.86 ft. =1° 50;' for a 10' Curved <br />