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CURVE TABLES Published by KEUFFEL & ESSER CO.;,,: HOW TO USE =CURVE TABLES Table' I: contains Tangents andExteinals to 1' curve'.` Tanand Ext. to any other radius maybe found nearly endugh,bydividing theTan. or Ext. opposite the given'Central Angle by the given degree of curve. ..To find Deg. of Curve; having the Central 'Angle and, Tangent: Divide Tan. opposite the -given Central Angle by the give ' n Tangent. To find Deg. of Curve, having the Central Angle and External: Divide Ext. opposite the given Central -Angle by the given Exterii,al. To find Nat. Tan. and Nat.tEx.,Sec. for any angle br TableJ.: Tan. or Ext. of twice the given'ahgle divided by the radius o :i 17 curve will be the Nat. Tan. or Nat. E)e. Sec. EXAjIPLk - Wanted a Curve withan Ext. of about. 12 ft. t. Angle. of Intersection or I. P.=23° 20' to. R.., at: Station 542+72. Ext. in Thb. 1 opposite 23' 20' 120.87 120.87 .12=10.07. Say a 10*,Curve. Tan. in Tab. I opp. 231 20'= 1183.1 1183.1_,10-_-i118.31: Correction for A. 239 2 ' 0' for a: 10° Cur. =0.16. 118.31+0.16=118.47�--corrected Tangent. - (If corrected Ext. is required find in sable way) Ang. 23' 20'=23.33*.=10=23333=L. C.- 2' 191, def - for sta.: .0 542 I. P. = sta.. 542+72 .4" 4921' 2 41 +50 Tan!_ 1 18.47 7' 191,= if a a 543 B. C. sta. :541-X53.53 , 9- 492, +50 2 L.C.= .2 .33.33 11' 40'= a a 543+ 86.86 E. C. = Sta. 543+.86..86 100 ---w53.53 =46.47 XX(def. for 1 ft. of 10'.Cur.) 139.411'.—, 2' 192'=def.,for sta. 542. Def: for 50 ft: = 2' 30' for. w 10Curve. Def. for 36.86 ft. 1* 50" for a 10' Curve. 4 "Zo lve� /0 �01-e Ao Z 7 11-1y Y -/.,o A110 18' 001, One Vo 01 9 Z A - [a fl— CURVE TABLES Published by KEUFFEL & ESSER CO.;,,: HOW TO USE =CURVE TABLES Table' I: contains Tangents andExteinals to 1' curve'.` Tanand Ext. to any other radius maybe found nearly endugh,bydividing theTan. or Ext. opposite the given'Central Angle by the given degree of curve. ..To find Deg. of Curve; having the Central 'Angle and, Tangent: Divide Tan. opposite the -given Central Angle by the give ' n Tangent. To find Deg. of Curve, having the Central Angle and External: Divide Ext. opposite the given Central -Angle by the given Exterii,al. To find Nat. Tan. and Nat.tEx.,Sec. for any angle br TableJ.: Tan. or Ext. of twice the given'ahgle divided by the radius o :i 17 curve will be the Nat. Tan. or Nat. E)e. Sec. EXAjIPLk - Wanted a Curve withan Ext. of about. 12 ft. t. Angle. of Intersection or I. P.=23° 20' to. R.., at: Station 542+72. Ext. in Thb. 1 opposite 23' 20' 120.87 120.87 .12=10.07. Say a 10*,Curve. Tan. in Tab. I opp. 231 20'= 1183.1 1183.1_,10-_-i118.31: Correction for A. 239 2 ' 0' for a: 10° Cur. =0.16. 118.31+0.16=118.47�--corrected Tangent. - (If corrected Ext. is required find in sable way) Ang. 23' 20'=23.33*.=10=23333=L. C.- 2' 191, def - for sta.: .0 542 I. P. = sta.. 542+72 .4" 4921' 2 41 +50 Tan!_ 1 18.47 7' 191,= if a a 543 B. C. sta. :541-X53.53 , 9- 492, +50 2 L.C.= .2 .33.33 11' 40'= a a 543+ 86.86 E. C. = Sta. 543+.86..86 100 ---w53.53 =46.47 XX(def. for 1 ft. of 10'.Cur.) 139.411'.—, 2' 192'=def.,for sta. 542. Def: for 50 ft: = 2' 30' for. w 10Curve. Def. for 36.86 ft. 1* 50" for a 10' Curve.