Laserfiche WebLink
Ks <br />CURVE TABLES <br />'Published by KEUFFEL &ESSER CO. <br />;HOW TO. USE CURVE TABLES <br />Table J. -contains Tangents ,and Externals to a V cfz.rve.,- Tan: and <br />kt. to any other radius may be found nearly enough, by dividing the Tan. <br />it Ext. opposite the given Central Angle by the given degree of: curve. <br />. To 'find' Deg. of Curve, having the Central Angle: and Tangent: <br />Divide Tan. opposite the given Central Angle by the given Tangent. <br />To find -.Deg. of Curve, having the'Central Angle and. -External: <br />Divide Ext.*opposite the given Central Angle by the give7i'F,kternal. <br />To And.Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tan. <br />)r Eit. of.twice the given angle divided by the radius of a P curve will <br />ie'the Nat. Tan. or Nat. Ex. Sec. <br />''..EXAMPLE - <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection or -1.. P.=23° 20' to she R. atiStation <br />542+72. <br />Ext. in Tab. I opposite 23 20'= 120.87 <br />120.87+12=10.07. Say'alO`Curve. <br />Tan. in Tab. 1, opp. 239 20'=1183.1 <br />4183.1--10" <br />—118.31. <br />Correction for. A. 23-.2 0' for a•10° Cur. =0.16-. <br />118.31+0.16 :-118.47- coir6 cted Tangent. <br />(If corrected -Eiti is required find in same way)' <br />Ang. 23* 20'=23.33 10=2.3333=L. C.. <br />' <br />2-`10i'^=def.'fors'ta'.'*,'• 542* 1. P. = 9ta. 542+72 <br />4.49 +50 'Tan..= <br />1 .'18.47'.; <br />911 543 <br />.7 a <br />9° 491'= B. C -- sta.' :541+53.53 <br />�'i -- +50' <br />11 ° 41: 1 2 .543+ L. C.= 2 .33.33 <br />0 <br />86.86, E. C. = Sta. .543+86.86 <br />100=53.53=46.47XX(def. for.1 ft. of 10° Cur'.)=139.41'= <br />2* 19" = def.'for sta. 542. <br />2 <br />_—Def. for 50 -ft. ­V -3W -for 1_40° Curve. - <br />Def. for 36.86ft.--1'50" for a 10° Curve. <br />IAA�,9.2­3 201 <br />> <br />IP*,"I*i�i26, <br />folcurve <br />0 <br />I <br />