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j -1 <br />'77: 71­7*CURVE TABLES <br />Published by'KEUFFEL & ESSER CO. <br />HOW TO USE CURVE TABLES <br />Table I. contains Tahgents,and, Externals to a V curve. Tan. and <br />Ext. to any other radius may be found nearly enough, by dividing the Tan. <br />or Ext. opposite the given Central Angle by the given degree of curve. <br />-To find Deg. of Curve-, -having the Central Angle and. Tangent: <br />'Divide Tan. opposite the given Central Angle by the given Tangent... <br />To find Deg. of Curve, having the Central Angle .and .Extermal: <br />Divide Ext. opposite the gNen Central Angle by th& giveii External. <br />To find Nat. Tan. a:nd.Nat. Ex., Sec.for any angle byTablel': Tan. <br />0iXI <br />'AL. of.tivice'the given: angle 'divided by the radius of a_1?curve Will <br />be. the Nat.:Tan. or Nat. Ex� Sec.. <br />Wanted a Cdrye,with an Ext. of about 12 ft. Anglef <br />of= Intersection ora I: J P. =23 20' to the R., at Station,- <br />542+72. <br />Ext. in 'Tab. I opposite 239 20' 120.87' <br />120.87 +12 10.07. ' Say' a 10*'.Curve. <br />Tan. in Tab. I i opp. 23*, 20'- 1183.1 Y, <br />1183.1'+10-118.31. <br />Correctionf6i.A. 23' 20' for a 10° Cur. =0.16 * <br />118M +0.16 118.47 =corrected Tangent. <br />'(If corrected Ext. is'required find in, same way)*: <br />Ang, 23' 20'=23.33°=10=2.3333=L. <br />C <br />.. <br />2-�1.gi'='def. for sta- 542' L P. = sta. 5412+72-' <br />- <br />4* 4912' It it it +50- Tan. = 1 48.41 <br />543 <br />BC. = sta.' - T54i +53.;5 4:153.53 <br />. . 1 <br />go 49'211 it cc +150' .33.33 <br />, I oe it it it <br />15"4 54�+. <br />86.86 E. C'=Sta: <br />54'3+86.86 <br />100,'53.53 _--�46.47 X3'(def. for l ft. of 100.Cur.) 139AV-, <br />2*. 19 =def.: for sta. 542. <br />Def; fof-50 ft:=2oM-for a 10° Curve. <br />Def. for 36.86 ft. 10 50 for a 10° Curve. <br />2 <br />z <br />I RA,c , 350 <br />> <br />curve <br />-------- <br />COA/ <br />Y <br />X <br />3 6 <br />L <br />/2-6 d <br />23,70 <br />F SS 7 <br />-7-08 <br />. <br />0, <br />15l.9a <br />/3,-0 <br />klb 3— <br />4. z+, <br />3 <br />S-, 2- X /, 3 < <br />7.oz . <br />7g,00 <br />4o�h% 4.7 <br />�.q <br />9-9.30 <br />zq, 0 <br />- <br />13 do <br />�1_3, 2 0 <br />b, is, <br />.10 <br />Q X33 <br />.4 el <br />141,7S <br />V <br />j -1 <br />'77: 71­7*CURVE TABLES <br />Published by'KEUFFEL & ESSER CO. <br />HOW TO USE CURVE TABLES <br />Table I. contains Tahgents,and, Externals to a V curve. Tan. and <br />Ext. to any other radius may be found nearly enough, by dividing the Tan. <br />or Ext. opposite the given Central Angle by the given degree of curve. <br />-To find Deg. of Curve-, -having the Central Angle and. Tangent: <br />'Divide Tan. opposite the given Central Angle by the given Tangent... <br />To find Deg. of Curve, having the Central Angle .and .Extermal: <br />Divide Ext. opposite the gNen Central Angle by th& giveii External. <br />To find Nat. Tan. a:nd.Nat. Ex., Sec.for any angle byTablel': Tan. <br />0iXI <br />'AL. of.tivice'the given: angle 'divided by the radius of a_1?curve Will <br />be. the Nat.:Tan. or Nat. Ex� Sec.. <br />Wanted a Cdrye,with an Ext. of about 12 ft. Anglef <br />of= Intersection ora I: J P. =23 20' to the R., at Station,- <br />542+72. <br />Ext. in 'Tab. I opposite 239 20' 120.87' <br />120.87 +12 10.07. ' Say' a 10*'.Curve. <br />Tan. in Tab. I i opp. 23*, 20'- 1183.1 Y, <br />1183.1'+10-118.31. <br />Correctionf6i.A. 23' 20' for a 10° Cur. =0.16 * <br />118M +0.16 118.47 =corrected Tangent. <br />'(If corrected Ext. is'required find in, same way)*: <br />Ang, 23' 20'=23.33°=10=2.3333=L. <br />C <br />.. <br />2-�1.gi'='def. for sta- 542' L P. = sta. 5412+72-' <br />- <br />4* 4912' It it it +50- Tan. = 1 48.41 <br />543 <br />BC. = sta.' - T54i +53.;5 4:153.53 <br />. . 1 <br />go 49'211 it cc +150' .33.33 <br />, I oe it it it <br />15"4 54�+. <br />86.86 E. C'=Sta: <br />54'3+86.86 <br />100,'53.53 _--�46.47 X3'(def. for l ft. of 100.Cur.) 139AV-, <br />2*. 19 =def.: for sta. 542. <br />Def; fof-50 ft:=2oM-for a 10° Curve. <br />Def. for 36.86 ft. 10 50 for a 10° Curve. <br />2 <br />z <br />I RA,c , 350 <br />> <br />curve <br />-------- <br />COA/ <br />Y <br />