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CURVE TABLES <br />Pubiished by KEUFFEL &,ESSER CO. <br />'HOW -70" USE. CURVE TABLES <br />7 <br />Table 'L,'contains Tangeits �azid Externals to a 1' curve. Tan. and <br />Ext. to any other radius pi4ybefound nearly enough, by dividing theTan. <br />or Ext. opposite the'kivefi,.Cential Angle by the given degree of curve. <br />.. To find:-' Deg.61 Curve, -having 'the Central Angle and' Tangent* <br />Divide Tan."opposite the given Central Ankle by the given Tangent. <br />- .,To find Deg. bf Ciirve,,Iaviiig'the :Central .Angle and External: <br />Divide Ext.'opposite the given Central Angle by . the giyeri External. <br />To find Nat. Tan. andNat–Ex. Sec.for any angle by,Table,I.: Tan. <br />r <br />o -,,Ext. of.tWice the given . ai . igle', di;iidedby the radius of a';1°, curve will <br />be.the Nat.;Tan. or Nat. Ex.' See. <br />EXAMPLE.:, <br />' <br />Wanted a Curve with an Ext. " of about 12 ft. Angle <br />of Intersection or,l. P.'=,23'.20' to%the-,R.-aCStation' <br />. <br />'542+72. <br />Ext. in Tat). I opposite 23* 20— 120.87 <br />120.87-12=M07.' Say a 10"Curve. <br />Tan. in Tab. Bopp. 23' 20'=1183.1 <br />1183.1-10-118.31.– <br />% <br />Correction <br />'ior'A.23-20'fora10*Cur.=0.16 <br />18.31 +0.16 =118,.47= corrected Tangent. <br />(If corrected Ext. is, required find in' same way <br />Ang,. 23' 20'=23.33°=10=2.3333=L. C.-: <br />' <br />20."19" =def. for sta' 542 .1. P. sta.. 54.2 <br />4 -49 _1.48.47 <br />-� +50. Tan. <br />- -------- -- <br />If= a a <br />2 1 4.d3. C. sta. 541+.3.53 <br />7' 49 543 <br />' 9'-4912'= + 2 .33.38 <br />41? 40'= -543 <br />86.86 E. Q.St a –543+86.86 <br />, <br />00–*,53.53 46.47 XX(def. for* 1 ft: of 10° Cur'.) 1.3.9.41. <br />2' 16 def.* for stq,542: <br />'Def. for -50 ft. -=2R.30' for a 10' Curve., <br />Def. for 36.86 ft. J* 502" for a 10° Curve. <br />e <br />9.23-201 <br />, Pi <br />lo*curve <br />cb <br />A/ <br />V <br />