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-? - -'.'.,CURVE: TALES. Published by KEUFFEL & ESSER HOW TO USE CURVE TABLESDxtern' . to An IL contains y other radius may be fou d nearly enough, by dividing the Tan- -ents and I 'Ext. opposite the given Central Angle by the given degree of curve. To find,Deg. of Curve; . having the Central ' nghe given Tangent- ii angle and t Tangent: iivide Tan. opposite the given Central Angle by id find Deg—of Curve,. -having the Centralh nglee-i EzExternal: )ivide Ext. opposite the given Central Angle by Table 1.: Tan. To find.Nat. Tan. and -N - Ex. Sec: fortune anglradius of a' 1° :curve will r.Ext. of twice the given Angle divided by e the Nat. Tan. or Nat. Ex: Sec, j EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of. Intersection 'or. ,I: P. =23° 20' to- the R, at Station 542+72. Ext. in•Tab.'I opposite 230 20'C Orbe 120.87-12=10:07: `_8ay,a10 , Tan. in Tab. 1, opp. 23° 20'= 1183.1 1183.1=10 =118.31: Correction for 'A. 23° 20' for a'10° Cur. =0.16 _ 118.31-}-0.16 =118.47 = corrected Tangent , , (If corrected Ext. is required find in same way)' Ang, 23° 20' � 23.33°=10=2.3333,,=L. C. . 2°.192'=def. forsta:: 542' I. P.:=sta. 542 }72 « 4 492' = «; . -x-50' `Tan. = 1..18.47 .7°`192, _ « u ' u 543.: B. C: =sta: 541+53.53 9° 49, = ,« +50 2 _.33,33 it ,11 40',--:- u ;« 86.86 E. C. Sta. 543 { 86:86 100-53.53 =.46.47X3'(aef. for lift. of 10° Cur. 139641'. 20 192' =.def. for -sta, 542. ' Def. for- 50 ft. 29 30' for a-10° Curve. Def. for 36.86 ft—V 502' for a 10° Curve. IO° curve � F �E �I I I II ,I e �IY \ fff,'II III tt�' i -? - -'.'.,CURVE: TALES. Published by KEUFFEL & ESSER HOW TO USE CURVE TABLESDxtern' . to An IL contains y other radius may be fou d nearly enough, by dividing the Tan- -ents and I 'Ext. opposite the given Central Angle by the given degree of curve. To find,Deg. of Curve; . having the Central ' nghe given Tangent- ii angle and t Tangent: iivide Tan. opposite the given Central Angle by id find Deg—of Curve,. -having the Centralh nglee-i EzExternal: )ivide Ext. opposite the given Central Angle by Table 1.: Tan. To find.Nat. Tan. and -N - Ex. Sec: fortune anglradius of a' 1° :curve will r.Ext. of twice the given Angle divided by e the Nat. Tan. or Nat. Ex: Sec, j EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of. Intersection 'or. ,I: P. =23° 20' to- the R, at Station 542+72. Ext. in•Tab.'I opposite 230 20'C Orbe 120.87-12=10:07: `_8ay,a10 , Tan. in Tab. 1, opp. 23° 20'= 1183.1 1183.1=10 =118.31: Correction for 'A. 23° 20' for a'10° Cur. =0.16 _ 118.31-}-0.16 =118.47 = corrected Tangent , , (If corrected Ext. is required find in same way)' Ang, 23° 20' � 23.33°=10=2.3333,,=L. C. . 2°.192'=def. forsta:: 542' I. P.:=sta. 542 }72 « 4 492' = «; . -x-50' `Tan. = 1..18.47 .7°`192, _ « u ' u 543.: B. C: =sta: 541+53.53 9° 49, = ,« +50 2 _.33,33 it ,11 40',--:- u ;« 86.86 E. C. Sta. 543 { 86:86 100-53.53 =.46.47X3'(aef. for lift. of 10° Cur. 139641'. 20 192' =.def. for -sta, 542. ' Def. for- 50 ft. 29 30' for a-10° Curve. Def. for 36.86 ft—V 502' for a 10° Curve. IO° curve