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I <br />----------------- <br />` <br />� ._��'� <br />�'• <br />1. � <br />P <br />� �. �`� <br />� � l <br />� . <br />2. <br />N > <br />' <br />' <br />I <br />CURVE TABLES- <br />Published by KEUFFEL & ESSER CO. <br />HOW 70' USE CURVE TABLES <br />'Table 1. contains Tangents and Externals to'a-1° curve: Tari. and <br />ext: to any other radius,may tie found nearly enough, by dividing the Tan.. <br />r Ext.opposite the given Central Angle by the given degree of curve. <br />;To 'find Deg. of Curve, having the Central Angle and.Tangent: <br />)ivide Tan.,opposite the given Central Angle by the given Tangent. <br />To' find -'Deg- of Cuive, , having the Central Angle ,and; External: <br />)wide Ext: opposite the:given Central Angle by the given External. <br />To find Nat. Tan. and Nat. Ex. Seca for any angle by Table I:: Tan. <br />r Ext. of,twice the given -angle divided by the radius of a,l°-curve will <br />e the Nat. Tan.=6i• Nat.,Ex Sec. <br />EXAMPLE <br />Wanted a Curve•with an;Ext: of about -12 ft'. -Angle <br />,of Intersection or I' P.-23° 20' to the R. at Siatiori <br />542+72., <br />Ext. in, Tab. I opposite23r 26' =120.87 <br />120.87-12=10:07. Say a 10, Curve. <br />Tan.;in Tab. I opp._23' 20'=.1'183.1• <br />1183.1'•-1l) =118:31. •:e <br />Correciion for -A. 23° 20' fora 10°•Cur 0.16,,-... <br />118.31+6A6 L.118.47 Tangent.'.' <br />(If corrected Exi. is.required'find in sante way) <br />t1ng: 23° 20''=23.33°-10=2:3333=L. C`, <br />;2°' 192' -=clef. -for sta. 542 .I. P. =sta. 512+72 <br />A- 49" = «. «; « +5'0 Tan. = 1 .18:47 <br />7 192' _ <` "' " 543. .B;, C. =sta.. ' 541+53.53 <br />9° 492'= +50 <br />11° 40'= , 543+ <br />L. C. 2 :"33.33 <br />86 E. C.=Sta. 543+86:86 . <br />100-53.53=4Ei.47X3'(def. for I ft. of 10° Cur.) =139.41'= <br />2 192'=de£. for sta. 542. <br />:.: lief. for 50 ft. =2° 30' for a 10° Curve". <br />Def:-for•36:86•ft.=1° 502' for a�10° Curve. <br />P1 I <br />10° Curve <br />y/ <br />001 <br />i <br />