|
Help
|
About
|
Sign Out
Home
Browse
Search
Pg 80
DaneCounty-Planning
>
Clerical
>
Sam
>
Fricky
>
FBs
>
390 A
>
Pg 80
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
3/10/2025 11:28:12 AM
Creation date
3/10/2025 11:28:10 AM
Metadata
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
Page 1 of 1
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
Show annotations
View images
View plain text
an. and <br />heTan. <br />curve. <br />ngent: <br />rent. <br />eternal: <br />rnal. <br />L: Tan. <br />rve will <br />CURVE TABLES <br />Published by KEUFFEL & ESSER CO. <br />HOW TO USE CURVE TABLES <br />Table I. contains Tangents and Externals to a 1° curve. T <br />- <br />Ext. to any other radius may be found nearly enough, by dividing 1 <br />or Ext. opposite the given Central Angle by'the given degree of <br />Z To find Deg. of Curve, having the Central Angle and To <br />Divide Tan. opposite the given Central Angle by the given Tariff <br />�✓ <br />To find Deg. of Curve, having theCentral Angle and E. <br />Divide Ext. opposite the given Central4ngle by the given Exte <br />-- <br />ro <br />t <br />3 <br />To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table <br />/ <br />or Ext. of twice the given, angle divided by the radius of a V cu <br />/ ; <br />be the Nat. Tan. or Nat. Ex: Sec. <br />(� <br />EXAMPLE <br />7" <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection or 1. P.=23° 20' to the R. at ,Station <br />542-72. <br />Ext. in Tab. I opposite 23° 20' =120.87 <br />- <br />— <br />120.87=12=10.07. Say a 10° Curve. <br />Tan. in 183.1 Tab. I o p. 2118.3= 1183.1 <br />Correction for A. 23* 118.31 0.16 118.47 = o 16 <br />=corrected Tangent. - <br />(If corrected Ext.'is required find in same way) <br />3� <br />I <br />Ang. 23° 20'=23.33°=10=2.3333=L. C. <br />2° 192"= def. for sta. 542 I. P. =sta. 542-F72 <br />4049211. _ " " x-50. Tan. = 1 .18.47 <br />7° 192' _ . u 543 <br />9° 492' _ " " +50 B. C. = sta..'. 541 53.5 <br />u u u L. C. = 2 .33.33 <br />11.o 40'_= 543+. <br />86.86 E. C.=Sta. 543 86.8E <br />S- <br />100=53.53=46.47X31(def. for 1 ft. of 10° Cur.) =139.41'= <br />�O <br />o <br />_ ' 2° 192' =def. for sta. 542. <br />Def. for 50 ft. =2° 30' for a 10° Curve. <br />Def. for 36.86 ft. =1° 50;' for a 10° Curve. <br />% . <br />. <br />I.P.An9.23°201 '. <br />Lj <br />_ • " 10P Curve. <br />�S <br />O <br />, <br />an. and <br />heTan. <br />curve. <br />ngent: <br />rent. <br />eternal: <br />rnal. <br />L: Tan. <br />rve will <br />
The URL can be used to link to this page
Your browser does not support the video tag.