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CURVE TABLES Published by KEUFFEL $ ESSER CO. Flaw TO USE CURVE TABLES Table I. contains Tangents and Externals to a V curve. Tan. and t. to any other radius may be found nearly enough, by dividing theTan. Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central Angle and Tangent: ride Tan. opposite the given Central Angle by the given Tangent. To find Deg. of Curve, having the Central Angle and External: gide Ext. opposite the given Central Angle by the given External. To find Nat. Tan, and Nat. Ex. Sec. for any angle by Table L: Tan. Ext. of twice the given angle divided by the radius of a 1° curve will the Nat. Tan. or Nat. Ex. Sec. EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or 1. P.=23° 20' to the R. at Station 542+72. Ext. in Tab. I opposite 23° 20'= 120.87 120.87 - 12 =10.07. Say a 10° Curve. Tan, in Tab. I opp. 23' 20'= 1183.1 1183.1 +10 =118.31. Correction for A. 23' 20' for a 1.0° Cur. =0.16 118.31+0.16 =118.47 = corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23° 20'=23.33'=10=23333=1— C. 2' 19 J'= def. for sta. 542 I. P.=sta. 542+72 V49j'= " °' " x-50 Tan.= 1 .18.47 7` 19#'= " e 543 9` 491'= " +50 B C. =sta. 541+53-53 53.53 11 ° 40' = " 7° 543+ L. C. = 2 .33.33 86.86 E. C. = Sta. iZ+86.86 100-53.53=46.47X3'(def. for 1 ft. of 10' Cur.)=139.41'= 2° 19-j'=def, for sta. 542. Def. for 50 ft. =2° 30' for a 10° Curve. Def. for 36.86 ft. =1' 50j' for a 10° Curve. a fil CURVE TABLES Published by KEUFFEL $ ESSER CO. Flaw TO USE CURVE TABLES Table I. contains Tangents and Externals to a V curve. Tan. and t. to any other radius may be found nearly enough, by dividing theTan. Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central Angle and Tangent: ride Tan. opposite the given Central Angle by the given Tangent. To find Deg. of Curve, having the Central Angle and External: gide Ext. opposite the given Central Angle by the given External. To find Nat. Tan, and Nat. Ex. Sec. for any angle by Table L: Tan. Ext. of twice the given angle divided by the radius of a 1° curve will the Nat. Tan. or Nat. Ex. Sec. EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of Intersection or 1. P.=23° 20' to the R. at Station 542+72. Ext. in Tab. I opposite 23° 20'= 120.87 120.87 - 12 =10.07. Say a 10° Curve. Tan, in Tab. I opp. 23' 20'= 1183.1 1183.1 +10 =118.31. Correction for A. 23' 20' for a 1.0° Cur. =0.16 118.31+0.16 =118.47 = corrected Tangent. (If corrected Ext. is required find in same way) Ang. 23° 20'=23.33'=10=23333=1— C. 2' 19 J'= def. for sta. 542 I. P.=sta. 542+72 V49j'= " °' " x-50 Tan.= 1 .18.47 7` 19#'= " e 543 9` 491'= " +50 B C. =sta. 541+53-53 53.53 11 ° 40' = " 7° 543+ L. C. = 2 .33.33 86.86 E. C. = Sta. iZ+86.86 100-53.53=46.47X3'(def. for 1 ft. of 10' Cur.)=139.41'= 2° 19-j'=def, for sta. 542. Def. for 50 ft. =2° 30' for a 10° Curve. Def. for 36.86 ft. =1' 50j' for a 10° Curve. a