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,CURVE TABLES <br />Gly <br />a <br />Published by KEUFFEL & ESSER CO. <br />.'NOW. TO- USE 'CURVE TABLES <br />" Table`L'cantains Tangents Externals to a 1 curve. Tan. and''. <br />! <br />} <br />,and <br />1,xt. to any other radius maybe found nearly enough,bydividing theTan. <br />degree curve. <br />iir Ext.'opposite. the given Central: Angle by'the given of <br />i <br />I To find Deg. of Curve, having, the Central Angle and Tangent: <br />` <br />Divide Tan:-opposite the given Central 'Angle by the given Tangent. <br />"1. Angle and External: <br />( <br />To find ,Deg.: of Curve; having the Central <br />Divide Ext, apposite the given Central Angle by the given External. <br />R <br />t } <br />�• <br />:.. <br />:.._-. To find-Nat. Tan. snd Nat. Ex.,Sec. £or any angle by Table L: Tan. <br />, <br />)r Ext.'oi twice'the given angle divided by the radius of a 1° curvewill <br />'I <br />i' )e the Nat..Tan. or Nat. Ez. Sec: <br />y <br />EXAMPLE <br />;. <br />'Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection `or. I: P.'=230 20' to. the R.: at Station <br />� <br />/ <br />542,x-72, <br />Ext. in Tab: I opposite 23° 20' =120.87 <br />i <br />120.87=12=10.07. Say a 10°. Curve. <br />- # Tan, in Tab. 11 opp. 23° 20' =1183.1 <br />t <br />` <br />l <br />' <br />11831: 101,18.31: .: <br />5 <br />rCor°rcction <br />forA. 23°•20' fora 10 Cur. =0.16 <br />118.31-1-0.16-'118:47= corrected Tangent., <br />(If cr�rrected Ext. is required find in same way)' ' <br />A ng.. 23° 20'= 23.33'-- 10 = 2.3333 = L. C. <br />' f2° 19y'= def, forsta.. 542 I. P. =sta. 5424 72 <br />Tan. 1 .18.47 <br />j-- 7°•19ar=.'E 543iS <br />B. C. = sta. 541+53:53 <br />t' 9° 49" - « g f +50 L. C. = 2.33.33 <br />i <br />11° 40. _ �, , ,t u 513+ <br />86.86. E. C.—Sta. 543-86.86 I <br />r <br />- <br />100-53 b3=46'.47X3'{def: for 1 ft. of 10° Cur.) 13'5.41'= <br />2' 19def. for sta. 542. <br />- Def. for 50 ft. =2° 30' for 10° Curve. <br />,Def, for 36.86 ft. =1° 501` for a 10° Carve. <br />k <br />} <br />�tr 4q! <br />- <br />% O _ <br />, <br />