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f;T CURVE. TABLES Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES Table I: contains Tangents and Externals to a I° curve. Tan. and ` to any other radius maybe found nearly enough, by dividing the Tan. Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central, Angle and Tangent: ride Tan_ opposite the given Central Angle by the given Tangent. e ` To find Deg. of Curve, having the Central Angle and External: Fide Ext.. opposite the given' Central Angle by the'given External. To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tan. Ext. of twice'the given angle divided by the radius of a 1° curve will the Nat. Tan. or Nat. Ex. See.' " EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of Intersecfion .or I. P–=23' 20' to the R. at Station 542+72. Ext. in Tab. I opposite 231 20' =120.87 s 120.87-:-12=10.07. Say a' 10° Curve. Tan. in Tab. Copp. 23° 20'=1183.1 1183.1=10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 t H r (If corrected Ext: is required find in same way) )r _ 2. 191, def. for sta. 542 LP. =sta. 542 } 72 1 4° 4911,= " +S0 Tan. = 7° 1911– a a a 543 – - 643 S. C. =sta. 541 53.53 - 9- 49, " L. C. = 2 .33.33 4 11* 40'= " " 543++50 '86:86 E. C. =Sta. ' 543+86.86 100-53:53=46.47X3'(def. for 1 ft. of 10° Cur.) =139.41'.'= C 2° 193'=def: for'sta. 542. Def. for 50 ft. =2* 30' for a 10° Curve. Def. for 36.86 ft. =1° 50;' for a 10° Curve, ,a - • io'�itu'va` " r 1 r` IR1;17, I — I,�I� (�f rte" • ,I ,_�.'�G",�� A�_- _-_ . Y s , lL� yu • f;T CURVE. TABLES Published by KEUFFEL & ESSER CO. HOW TO USE CURVE TABLES Table I: contains Tangents and Externals to a I° curve. Tan. and ` to any other radius maybe found nearly enough, by dividing the Tan. Ext. opposite the given Central Angle by the given degree of curve. To find Deg. of Curve, having the Central, Angle and Tangent: ride Tan_ opposite the given Central Angle by the given Tangent. e ` To find Deg. of Curve, having the Central Angle and External: Fide Ext.. opposite the given' Central Angle by the'given External. To find Nat. Tan. and Nat. Ex. Sec. for any angle by Table I.: Tan. Ext. of twice'the given angle divided by the radius of a 1° curve will the Nat. Tan. or Nat. Ex. See.' " EXAMPLE Wanted a Curve with an Ext. of about 12 ft. Angle of Intersecfion .or I. P–=23' 20' to the R. at Station 542+72. Ext. in Tab. I opposite 231 20' =120.87 s 120.87-:-12=10.07. Say a' 10° Curve. Tan. in Tab. Copp. 23° 20'=1183.1 1183.1=10=118.31. Correction for A. 23° 20' for a 10° Cur. =0.16 118.31+0:16 118.47 =corrected Tangent. - (If corrected Ext: is required find in same way) Ang.23°20'=23.33°=10=2.3333=L. C. 2. 191, def. for sta. 542 LP. =sta. 542 } 72 1 4° 4911,= " +S0 Tan. = 7° 1911– a a a 543 – - 643 S. C. =sta. 541 53.53 - 9- 49, " L. C. = 2 .33.33 4 11* 40'= " " 543++50 '86:86 E. C. =Sta. ' 543+86.86 100-53:53=46.47X3'(def. for 1 ft. of 10° Cur.) =139.41'.'= ; 2° 193'=def: for'sta. 542. Def. for 50 ft. =2* 30' for a 10° Curve. Def. for 36.86 ft. =1° 50;' for a 10° Curve, ,a - • io'�itu'va` "