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CURVE TAMES' <br />Published by KEUFFEL & ESSER CO. <br />HOW TO USE CURVE TABLES <br />ITable L contains Tangents and Externals to a 1° curve. ` Tan. and ` <br />(t. to any other radius maybe found nearly enough', by dividing the Tan. <br />jExt. opposite the given Central Angle by the given degree of curve. <br />f To find'Deg. of Curve, having,the Central,Angle and,Tangent: <br />`Tvide Tan. opposite the given Central Angle by the given Tangent. <br />o find Deg. of Curve, .having -.the Central'Angle and External: <br />vTo find Nat. Tan, anosite d Nat. Ex.tSec..' for anl Angle y anglthe e by TbeExternal. <br />I : Tan. <br />Ext. of twice the given angle divided by the radius of a P curve will <br />the Nat. Tan. or Nat. Ex: See. <br />EXAMPLE <br />Wanted a Curve with an Ext. of about 12 ft. Angle <br />of Intersection .or 1. P.=23':20-1 to .the R. at Station <br />542-72. <br />Ext. in Tab. I opposite 23°20'=120.87 <br />420.87=12.10.07. Say`a 10° Curve. <br />� <br />Tan. in Tab. I opp. 23° 20'=1183.1 <br />r i 1183.1=10=118.31. <br />Correction for A. 23° 20' for a 10° Cur. =0.16 <br />118.31,+0.16=118.47=corrected Tangent. <br />'M corrected Ext. is required find in same way) <br />Ang. 23° 20'=23.33°=10=2.3333=L. C. <br />2° 191'=def. for sta. 542 1. P. :sta. 542+72 <br />4-4911= «_ <br />+'0 Tan. = 1 .18.47 <br />+° 191= 543 <br />9.49j', w a u +50 B• C. =sta. 541+53.53 <br />543+ L. C.= 2 .33.33 <br />86.86.. E. C. =Sta. 543+86.86 <br />100-53.53=46.47X3'(def. for 1 ft. of 10° Cur.)=739.41'= <br />20 191' =def, for sta. 542. <br />Def. for 50 ft. =20 30' for a 10° Curve. <br />Def. for 36.86 ft. =1° 501' for a 10° Curve. <br />M <br />