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CURVE TABLES <br />dished by KEUFFE! & ESSER CO. <br />OW TO USE CURVE TABLES �- <br />is Tangents and Externals to a V curve. Tan. and <br />ius may be found nearly enough, by dividing the Tan. <br />given Central Angle by the given degree of curve. <br />Curve, having the Central Angle and Tangent: <br />the given Central Angle by the given Tangent. <br />Curve, .having the Central Angle and External: <br />the given Central Angle by the given External. <br />1.. and Nat. Ex. See. for any angle by Table i.: Tan. <br />I <br />iven angle divided by the radius of'a 1° curve will <br />Vat. Ex. Sec. <br />EXAMPLE <br />a Curve with an Ext. of about 12 ft. Angle <br />in or I. P. = 23° 20' to the R. at Station <br />in Tab. I opposite 23° 20'= 120.87 <br />.87+12=10.07. Say a 10° Curve. <br />i. in Tab. I opp. 23° 20'=1183.1 <br />1283.1-10=218.31. <br />on for A. 230 20' for a 10° Cur. =0.16 <br />1-0.16=118.47=corrected Tangent. <br />:ted Ext. is required find in same way) <br />23° 20'=23.33 X10=2.3333=L. C. <br />tr:sta. 542 1. P.=sta. 542+72 <br />x-50 an. = 1 .18.47 <br />543 B C =sta. 541+53.53 <br />+50 <br />` 543+ L. C. = 2 AIM <br />86.86 E. C.=Sta. 543+86.86 <br />17X3'(def. for 1 ft. of 10° Cur.) <br />2° 19;'=def. for sta.542. <br />Dr- 50 ft. =20 30' for a 10° Curve. <br />r 36.86 ft. =10 50;' for a 10° Curve. <br />Ey <br />Ax <br />ai <br />!V <br />IS <br />Pu <br />M <br />Table I. contai <br />i. <br />xt. to any other rat <br />r Ext. apposite the <br />To f nd Deg. o <br />_ <br />)ivide Tan. opposit <br />@- To find Deg. o. <br />i <br />)ivide Ext. opposit, <br />i <br />To find Nat. Ta <br />r Ext. of twice the <br />41/-. 'e the Nat. Tan. orr <br />-+ <br />/G <br />Wanted <br />/ <br />Q �4 ! Of Intersecti <br />< <br />/ 542+72. <br />' <br />t <br />Ext <br />12[ <br />q <br />Ta <br />�i! <br />_------— <br />r <br />✓4'r <br />Correct <br />t� <br />t t 118.31 <br />corrc <br />Ang. <br />20191'=cief.f <br />v� <br />� 40 49, « <br />i l s�ir'Z 7° 191'= a <br />A <br />I In <br />a2 <br />.i • �o <br />Ci <br />! <br />r fo r <br />100-53.53=46 <br />es <br />' <br />p <br />v <br />Def. 1 <br />7 , , Def. ft <br />% <br />.. 719 <br />/{ <br />7, <br />4e'S�i3 <br />1 <br />CURVE TABLES <br />dished by KEUFFE! & ESSER CO. <br />OW TO USE CURVE TABLES �- <br />is Tangents and Externals to a V curve. Tan. and <br />ius may be found nearly enough, by dividing the Tan. <br />given Central Angle by the given degree of curve. <br />Curve, having the Central Angle and Tangent: <br />the given Central Angle by the given Tangent. <br />Curve, .having the Central Angle and External: <br />the given Central Angle by the given External. <br />1.. and Nat. Ex. See. for any angle by Table i.: Tan. <br />I <br />iven angle divided by the radius of'a 1° curve will <br />Vat. Ex. Sec. <br />EXAMPLE <br />a Curve with an Ext. of about 12 ft. Angle <br />in or I. P. = 23° 20' to the R. at Station <br />in Tab. I opposite 23° 20'= 120.87 <br />.87+12=10.07. Say a 10° Curve. <br />i. in Tab. I opp. 23° 20'=1183.1 <br />1283.1-10=218.31. <br />on for A. 230 20' for a 10° Cur. =0.16 <br />1-0.16=118.47=corrected Tangent. <br />:ted Ext. is required find in same way) <br />23° 20'=23.33 X10=2.3333=L. C. <br />tr:sta. 542 1. P.=sta. 542+72 <br />x-50 an. = 1 .18.47 <br />543 B C =sta. 541+53.53 <br />+50 <br />` 543+ L. C. = 2 AIM <br />86.86 E. C.=Sta. 543+86.86 <br />17X3'(def. for 1 ft. of 10° Cur.) <br />2° 19;'=def. for sta.542. <br />Dr- 50 ft. =20 30' for a 10° Curve. <br />r 36.86 ft. =10 50;' for a 10° Curve. <br />Ey <br />Ax <br />ai <br />!V <br />