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. Tan. and <br />ing theTan. <br />�e of curve. <br />I Tangent: <br />Tangent. <br />d External: <br />External. <br />able I.: Tan. <br />I' curve will <br />,ngle <br />ition 0c,t� <br />-72 <br />18.47 <br />x53.53 <br />. 33.33 <br />rs6.a6 <br />�ti7 5�o.i <br />33 <br />8' <br />D <br />CURVE TA��ES <br />A <br />�F. Published by KEUFFEL & ESSER CO. <br />7 j <br />�` ,7r' HOW. TO USE CURVE TABLES <br />'d w4 ''- ; Table I. contains Tangents and Externals to a 1° curvf <br />b dNic <br />`� it. to any other radius: may be found nearly enough,' Y <br />p <br />p � <br />?v a. <br />-6`�' <br />-� <br />; ETo find Deg• ofhe gCu Curve, iven ehaving tutts h'e Cle ent athe gAngleiven �an <br />ivide Tan. opposite the given Central Angle by the. given <br />e-a <br />To find Deg. of Curve,, having the -Central Angle a� <br />�� <br />$$ <br />T, -M <br />176, <br />`�6 <br />ivide Ext. opposite the,given Central Angle by the given <br />To find Nat. Tan. and Nat. Ex. Sec. far any angle by,1 <br />" 9i <br />/6 ' <br />Ext. of twice the given angle divided tiy'the radius of a <br />rlv�_ <br />ffi' <br />�7a �7 <br />y <br />the Nat. Tan. or Nat~"•Ex,.Sec. <br />i '`EXAMPLE' .,: <br />;: <br />Wanted a Curve with an Ext. of about 12 Et. ! <br />Z <br />117 � I <br />/ 5� <br />(I <br />r' <br />73 <br />of _ Intersection or I.: P. =23° 20' to the R. at 5t <br />542+i2. <br />Ext. in Tab. I opposite 23° 20'= 120.87 <br />1:20.87 :-12=10.07. Say a 10° Curve. <br />in Tab. I opp. 23° 20'= I1S3.1 <br />y <br />7b 0-� <br />i3 <br />� f <br />/• <br />Q.p!1 <br />/G <br />? 1 ,F Q9 <br />fi���i'Z <br />ire ,. 57Tan. <br />971, ¢ <br />f,', 31 <br />�., 1183.1=10=118.31. <br />Correction for A. 23° 20' fora 10° Cur. =0.1fi <br />I 118.31-}-0.16=118.47=correcte6 Tangent. <br />If correcte <br />Ang.-2d Ext. is required find in same way. <br />( o.3°m,20=23-33 °-10=2.3333=1,. C. <br />5" <br />971, Iq <br />is,,'F/ <br />7,. f 75 <br />�' <br />rar-� Z,/. <br />fi <br />- 2° 19 Z'=def. for sta. '�•_ 542 I. P. =ata. 542 <br />�J. - <br />�/)%"! <br />`=,•;._. 4° 49" _ ,< F< „ x-50 Tan. = 1 <br />u ° ° <br />7` U <br />l ''% <br />I <br />I° 192'_ 543 B. C.=sta. 541- <br />1 +J° 491'= « ° ° +50 2 <br />11° 40'= ° ° 54.3- L. C.= <br />/ <br />� 7 <br />,3 <br />� / . <br />N -3100-53.53 <br />86.86 E. C.=Sta. 543. <br />�46.47XS'(def. for 1 it. of 10° Cur.) =135 <br />/ <br />ZZ <br />%7!, 43 <br />Z1 � � <br />�2ffi', <br />2° 192' =def. for sta. 542. <br />Def. for 50 ft, =2' 30'.1or a 10° Curve. <br />lief. for 36.86 ft. =1° 50,' fora 10"Curve. <br />p <br />ip <br />J <br />_ e <br />" � ii 1.P.An9-23.20• <br />10•Gurve <br />�J ! <br />. Tan. and <br />ing theTan. <br />�e of curve. <br />I Tangent: <br />Tangent. <br />d External: <br />External. <br />able I.: Tan. <br />I' curve will <br />,ngle <br />ition 0c,t� <br />-72 <br />18.47 <br />x53.53 <br />. 33.33 <br />rs6.a6 <br />