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/3/ 3S� <br />'/o <br />0 <br />210 - <br />TRIGONOMETRIC <br />3a <br />TRIGONOMETRIC FORMULAE <br />R <br />6a <br />. c w � <br />vu a a a <br />� b' C At C `4 L 1 � <br />Right Triangle Oblique Triangles , <br />Solution of Right Triangles <br />For Angle A. sin= ° , coo= b , tan= a , cot = b , sec = a , cosec = e <br />c o b a b a <br />(liven Required a 2 <br />Ca,b A,B;o tan A=b=cotB,c= az+ 2=a V,+a2 <br />2 <br />a, a A, B, b sin A = = cos B, b = �/ (c-� ¢) (c —a = e 1— o <br />A, a B, b, c B = 900—A, b = a cot A, c = <br />sin <br />A. <br />' b <br />A, b B, a, c B = 90°—A, a = b tan A, c= � cos A., <br />{ A, c B, a, b I B = 90°—A, a = e sin A, b = c cos A, <br />Solution of Oblique Triangles <br />i (liven Required a ein B¢sin C <br />A, B, a b, c, C b = in A , C = 180°—(A + B), c = sin A <br />l,- b sin A a sin C <br />F <br />A, a, b B, c, Csin B= a ,C = 180°—(A { B), c = sin A <br />a, b, C A, B; o A+B=180°—C, tan lj(A—B)=(a—b) can' (A+B), <br />a + b <br />a sin C <br />c= <br />sin A <br />a, b, c A, B, C s=a+2+c,einA=Y(s ba <br />sin JB=1l(s—a) s� ,C=180°—(A+B) <br />Y a G <br />—a+b-{ a <br />a, b, c Area s— 2 ,area = V15(s—a s— s—c <br />A, b, c Area area = b a sin A <br />2 <br />a= sin B sin C <br />A, B, C, a Area area = 2 sin A <br />REDUCTION TO HORIZONTAL <br />Horizontal distance= Slope distance multiplied by the <br />cosine of the vertical angle. Thus: slope distance =319.4 ft. <br />tsope Vert. angle=51 101. From Table, Page IX. cos 50 10'= <br />oPe ass y 9959. Horizontal distance=319.4X.9959=31&09 ft. <br />g1 XaXe x Horizontal distance also=Slope distance minus slope <br />Qe distance times (1—cosine of vertical angle). With the <br />same figures as in the preceding example, the follow - <br />Horizontal distance ing result is obtained. Cosine 60101=.9959.1—.8959=.0041. <br />319.4X.0041=1.31.319.4-1.31=31&09 ft. <br />When the rise is known, the horizontal distance is approximately:—the slope dist- <br />ance less the square of the rise divided by twice the slope distance. Thus: rise=14 M. <br />slope distance=3028 ft. Horizontal distance=3020— 14 X 14 =302.8-0 32=30228 ft. <br />2X=8 <br />MACE IN V. S. A. <br />