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TRIGONOMETRIC FORMULR_ <br />JT 1> B <br />a c a c a <br />AA�b C A b C <br />Right Triangle, Oblique Triangles <br />Solution of Right Triangles <br />a b a b c c <br />For Angle A. sin = o ,cos = ,tan = b ,cot = ,sec = b , cosec = a <br />Given Required I <br />a, b A, B ,c tan A = b = cot B, e = -V-a—'2+-Xy = a I f az <br />a, c A; B, b sinA= =cos B,b=�)c1— <br />/(c+a c—¢ as <br />C =�ar <br />A, a <br />B, b, c _ <br />B = 90°—A, b = a cot A, c = a <br />sin A. <br />A, b <br />B, a, c <br />B = 90°—A, a = b tan A, c = b <br />cog A. <br />A, c <br />B, a, b <br />B = 90°—A, a = c sin A, b = e cos A., <br />Solution of Oblique Triangles <br />Given <br />A J)—,- <br />Required <br />b, c, C <br />b = a sin B C _ 180°—(A + B), e — asin C <br />' <br />' <br />sin A sin A <br />A,a,b <br />B,e,C <br />sinB=.beaA,C=180°—(A+B),c= <br />sin <br />0. b, C <br />A, B, e <br />A+B=180'—C, tan J (A—B)= (a—b) tan (A } B) <br />a -}- b <br />a sin C <br />_ <br />c gin A <br />C <br />a+ °,,in <br />a, b, a <br />A, B, C <br />a = -A= `�(J <br />_ <br />J a J—e <br />sin 118=� ( a ),C=180°—(A-{-B) <br />e <br />a, b, c <br />Area <br />g = a+2 +c <br />A, b, c <br />Areab <br />e sin A <br />area = <br />2 <br />a= sin B sin C <br />A, B, C, a <br />Area <br />area = <br />2 sin A <br />REDUCTION TO HORIZONTAL <br />Horizontal distance= Slope distance multiplied by the <br />edsine of the vertical angle. Thus: slope distance =319..4 ft <br />'From <br />a�sVs <br />Vert. angle= 50 101. Table. Page IX. cos 5010'= <br />$1 oQe <br />ti 9959. Horizontal distance=319.4X.9959=318.09 ft. <br />Horizontal distance also=Slone distance minus slope <br />Ao�1e <br />e <br />a distance times (1—cosine of vertical angle). With the <br />same figures as in the preceding example, the follow - <br />Horizontal distance <br />ing result is obtained. Cosine 5° 10'=.9959.1—.9959=.0041. <br />319.4X.0041=1.31. 319.4-1.31=318.09 ft. <br />When the rise is known, the horizontal distance is approximately:—the slope dist- <br />ance less the square of the rise divided by twice the slope distance. Thus: rise=14 ft, <br />slope distance=3028 it. <br />Horizontal distance=302.6— 14 X 14 _3M6-0.32=302 28ft. <br />2 X 3026 <br />MADE IN U. S. A. <br />�t� <br />A <br />